0=10v^2-13v+3

Solution for 0=10v^2-13v+3 equation:

0=10v^2-13v+3

We move all terms to the left:

0-(10v^2-13v+3)=0

We add all the numbers together, and all the variables

-(10v^2-13v+3)=0

We get rid of parentheses

-10v^2+13v-3=0

a = -10; b = 13; c = -3;
Δ = b2-4ac
Δ = 132-4·(-10)·(-3)
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-7}{2*-10}=\frac{-20}{-20}
=1
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+7}{2*-10}=\frac{-6}{-20}
=3/10
$